Question

A wire of length 2.5m has a percentage strain of 0.012% under a tensile force. Determine the extension in the wire ​

Answer 1

Original length, L = 2.5m

Strain =∆L / L = 0.012%

$\frac{0.012}{100}$

∆L = Stain × L

or

∆L = extension = $\frac{0.012}{100}$ × L

0. 012 × 2.5 / 100

3 × ${10}^{4}$

0.3 mm

Answer 2

Answer:

0.3 mm

Explanation: