Question

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:

(1) (4-π)x = πr

(2) x = 2r

(1) 2x = r

(2) 2x = (π + 4)r

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Answer 1

Answer:

wire of length 2 units is cut into two parts which are bent respectively to form a square of side=x units and a circle of radius=r units. If the sum of the areas of the square and the circle so formed is minimum, then: 2x=(π+4)r. (4−π)x=πr.

Answer 2

Answer:

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side=x units and a circle of radius=r units. If the sum of the areas of the square and the circle so formed is minimum, then: 2x=(π+4)r. (4−π)x=πr.

Explanation:

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