A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:
(1) (4-π)x = πr
(2) x = 2r
(1) 2x = r
(2) 2x = (π + 4)r
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Answer:
X = 2r
Explanation:
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