a wire of length 200 cm is cut into two parts and each part is bent to formulate a square. if the area of the larger square is 9 times of the smaller square, find the perimeter of the larger square.
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Assume that the area of the smaller square = 1 sq cm
∴ length of each side of the square = 1 cm
∴ Perimeter of the smaller square = 4 cm
∴ the area of the larger square would be 9 sq cm
∴ length of each side of the square = 3 cm
∴ Perimeter of the larger square = 12 cm
We can see that the ratio of the perimeter of the smaller square : larger square = 4:12 = 1:3
∴ the perimeter of the smaller square = 200 x (1÷3) = 66.666 cm = 66.67 cm
which gives us the perimeter of the larger square = 200 cm - 66.67 cm = 133.33 cm
∴ length of each side of the square = 1 cm
∴ Perimeter of the smaller square = 4 cm
∴ the area of the larger square would be 9 sq cm
∴ length of each side of the square = 3 cm
∴ Perimeter of the larger square = 12 cm
We can see that the ratio of the perimeter of the smaller square : larger square = 4:12 = 1:3
∴ the perimeter of the smaller square = 200 x (1÷3) = 66.666 cm = 66.67 cm
which gives us the perimeter of the larger square = 200 cm - 66.67 cm = 133.33 cm
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