a wire of length 22 cm is bent in the shape of a circle. find the area of the circle ,if the wire is bent in the form of a square find its area which figure includes more area of the circle or the square (( use Pi equals to 22 upon 7)).....
Answers
Case 1:
Given:
A wire of length 22 cm is bent in the shape of a circle.
To Find:
The area of the circle.
Formulas Used:
Circumference of a circle = 2πr
Area of a circle = πr squared
Solution:
Circumference of the circle = 22 cm
By using the formula, we get
2πr = 22 cm
or, r = 22/2 × 7/22 = 7/2 = 3.5 cm
The radius of the circle is 3.5 cm.
Area of the circle = πr squared
Area of the circle = 22/7 × 3.5 × 3.5
Area of the circle = 11 × 3.5
The area of the circle is 38.5 cm squared.
Case 2:
Given:
The wire of length 22 cm is bent in the form of a square.
To Find:
The area of the square.
Formulas Used:
Perimeter of a square = 4 × Side
Area of a square = Side squared
Solution:
Perimeter of the square = 22 cm
By using the formula, we get
4 × Side = 22 cm
Side = 22/4 = 5.5 cm
The length of each side of the square is 5.5 cm.
Area of the square = Side squared
Area of the square = 5.5 × 5.5
The area of the square is 30.25 cm squared.
Answer:
The area of the circle is greater than the area of the square.