a wire of length 3.0 CM carrying a current of 10 A is placed inside a solenoid and perpendicular to its Axis the magnetic field inside the solenoid is given to be 0.27 D what is the magnetic force on the wire
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Explanation:
θ=90o
F=BIlsinθ=8.1×10−2N
Direction of force can be obtained from Fleming's left hand rule.
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