Question

A wire of length 3.7m and diameter of 1.62mm has a 4.7 kg load applied to its ends. Calculate the length by which the wire will stretch. Y=185GPa. Assume PI=3.14 and g=9.8m/sec^2 (Answer In mm)

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Answer 1

Answer:

• The wire will stretch by 0.45 mm

Explanation:

Given,

length of wire (l) = 3.7 m

diameter (d) = 1.62 mm

radius (r) = 0.82 mm

Young's modulus (Y) = 185 GPa

From Young's modulus we know that,

$\longrightarrow\sf Y = \Bigg(\dfrac{F}{A}\Bigg) \: . \: \Bigg(\dfrac{l}{\Delta l}\Bigg)$

Now refer the attachment.