Question

A wire of length 32 cm is converted into a parallelogram of length 10 cm. The width of the parallelogram is

Answer 1

Required Answer :

The width of the parallelogram = 6 cm

Given :

• Length of the wire = 32 cm
• Length of the parallelogram = 10 cm

To find :

• Width of the parallelogram = ?

Solution :

Length of the wire = Perimeter of the parallelogram

So, perimeter of the parallelogram = 32 cm

Formula of perimeter of parallelogram :

• Perimeter of parallelogram = 2(l + b)

where,

• l denotes the length of the parallelogram
• b denotes the base of the parallelogram

Substituting the values :

→ 32 = 2(10 + b)

→ 32/2 = 10 + b

→ 16 = 10 + b

→ 16 - 10 = b

→ 6 = b

→ The value of b = 6

Therefore, the width of the parallelogram = 6 cm

Answer 2

❆ ϲοиϲєρτ :-

In this question, we have been asked to calculate the width of the parallelogram which is made out of a wire of length, 32 cm.

So, we can say that,

Length of the wire = Perimeter of the parallelogram.

Now, we can easily find out the width of the parallelogram by the using the concept of "Perimeter".

❆ ƒοямυℓα υѕє∂ :-

$\boxed{ \sf \blue ❆\: \red{ perimeter \: of \: parallelogram \: = 2(l + b)}}$

Where,

• "l" denotes length
• "b" denotes Breadth

Now we will simply put the given values to get the required answer.

$\sf \leadsto \: 32 \: cm \: = 2 \: ( \: 10 \: cm + b \: ) \\ \sf \leadsto \: 32 \: cm \: = 20 \: cm \: + 2b \: \: \: \: \: \\ \sf \leadsto \: 2b \: = 32 \: cm - 20 \: cm \: \: \: \: \: \: \\ \sf \leadsto \: b \: = \frac{12}{2} = 6 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\boxed{ \sf \pink{ \therefore {breadth \: of \: the \: parallelogram \: = 6 \: cm}}}$