Question

a wire of length 5.0m and diameter 2.0mm extends by 0.25 mm when a force of 50N was used to stretch it from its end
Calculate a. the stress on the wire
b. strain in the wire

Answer 1

Explanation:

L = 5

d = 2*10^-3

r = 10^-3

A = pi r^2 = pi (10^-6)

stress = 50 N / 3.14*10^-6 = 15.9 * 10^6 Newtons/ m^2

strain = delta L/L = .25*10^-3 / 5 = .05 *10^-3 = 50 * 10^-6 m

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Answer 2

Answer:

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