Math, asked by ak07696163gmailcom, 18 days ago

A wire of length 56 m is bent in the form
of a circle. Find the radius of the circle.
Also find the area. If the same wire is
bent in the form of a square what will be
side and area. Which figure encloses
more area, the circle or the square?​

Answers

Answered by ItzHannu001
2

Answer:

Given:-

  • Length of wire = 56m

To find:-

  • Radius of circle
  • Area of circle
  • Side of square
  • Area of square

________________________

 \tt {\boxed {\red{ \tt \large{For  \:  \: Circle}}}}

Since the wire of length 54m is bent in the form of a circle

So, Length of wire = Circumference of circle = 56m

Hence, Circumference of circle = 2πr

56m. = 2πr

radius. = 56×7 / 44 = 8.90mm

So, Area of circle = πr2

= 22/7 × 8.9 = 248.945 m^2

 {\boxed {\red{ \tt{For Square}}}}

Since the wire of length 54m is bent in the form of a square

So, Length of wire = perimeter of square = 56m

Hence, Perimeter of square= 56m

4×s = 56

s = 56/4 = 14m

So, Area = (side)^2

= (14)^2 = 196m

________________________

Since Area of circle is greater than area of square

So, We see that Circle encloses more area than square

Answered by preeti353615
1

Answer:

  • Area of circle = 248.95 sq. m
  • Area of square  = 196 sq. m.
  • Circle encloses more area.

Step-by-step explanation:

A wire of length 56 m is bent in the form of a circle.

Means circumference of the circle is 56 m

step 1: Find radius and area of the circle

The circumference of circle =2 × π×r

56 m= 2 × π×r

π×r = 28

r = 28 × 7/22

r = 8.9 cm

Area of circle = \pi r^2

= = \frac{22}{7} \times (8.9)^2\\= 248.95 sq. m

Step 2: Side and area of square

If the same wire is bent in the form of a square what will be the side and area.

circumference of circle = perimeter of square = 56 m

4 side = 56

side = 56/4 = 14 m

So, the side square is 14 m

Area of square = side × side = 14 × 14 = 196 sq. m.

Step 3: Compare the area of the circle or the square

Area of circle = 248.95 sq. m

Area of square  = 196 sq. m.

So, Circle encloses more area.

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