Question

A wire of length 5m and of area of cross section 10^-6 m^2 is stretched by 2 mm. If the tension developed in the wire is 50 N, what is the young's modulus?​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A wire of length 5m and of the area of cross-section 10^-6 m^2 is stretched by 2 mm. If the tension developed in the wire is 50 N. The young's modulus of the wire will be  $125\times 10^{9} N/m^{2}$

Explanation:

Young's modulus of a material (Y) is given by,

Y = $\frac{FL}{Al}$ ....(1)

where

F - Tension on the wire

L - Initial length of the wire

l -  Extended length

A - Area

Given,

L     =  5 m

l      =  2 mm  = $2\times 10^{-3}$ m

A     =  $10^{-6}$ $m^{2}$

F      =  50 N

Using equation (1),

$Y= \frac{FL}{Al} = \frac{50\times5}{10^{-6}\times2\times 10^{-3} }$

We get,

 Y =  $125\times 10^{9} N/m^{2}$

   

Ans :

• Young's modulus of the wire  = $125\times 10^{9} N/m^{2}$