A wire of length 5m has a resistance of 2.0 ohm. calculate the resistance of wire of le ngth 1m
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We know that,
R = (rho)*length/Cross Sectional Area
Since, the length of the wire has doubled, hence there will definitely be some change in cross sectional area.
Now we know that, volume = Mass/Densityand since neither mass nor density has changed due to change in length, thus volume must remain constant.
We further know that,
Volume = Length * Cross Sectional Area
This implies that, due to doubling the length of wire, the cross sectional area will become half for volume to remain constant.
Thus we get, new cross sectional area = (1/2) of old cross sectional area
New length = 2 * old length of wire.
Putting these value into t
R = (rho)*length/Cross Sectional Area
Since, the length of the wire has doubled, hence there will definitely be some change in cross sectional area.
Now we know that, volume = Mass/Densityand since neither mass nor density has changed due to change in length, thus volume must remain constant.
We further know that,
Volume = Length * Cross Sectional Area
This implies that, due to doubling the length of wire, the cross sectional area will become half for volume to remain constant.
Thus we get, new cross sectional area = (1/2) of old cross sectional area
New length = 2 * old length of wire.
Putting these value into t
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