Question

A wire of length 5m is twisted through 30° at free end. If the radius of wire is 1 mm, the shearing strain in the wire is

Answer 1

Shear strain in the wire is 0.18°

Shear strain is calculated by the formula

Shear strain=$\frac{rΦ}{l}$

Plugging the values in the above equation

Shear strain=((0.001*30*(π/6)/5)

=0.0031 rad

=0.0031*180/π=0.18°

Answer 2

L = 5m and the phi= 30 degree = 30 * pi/180 = pi/6

L * thetha = r * phi

5 * thetha = 10^-3 * pi/6

Thetha = 10^-3 * pi/6*5

Thehta = 10^-3 * 3.14/30

Thetha = 10^-4 * 3014/3 radius

Hence,

3.14/3 * 10^-4 * 180/3.14 hour

10^-4 * 60 * 60 min

3600 * 10^-4 min

0.36