A wire of length 72 cm is bent to form a
right-angled triangle of hypotenuse 30 cm.
Find the lengths of the other two sides.
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Answered by
2
Answer:
a+b+5=12
a+b=7⇒a=7−b...(1)
a2+b2=52
a2+b2=25...(2)
From (1) and (2)
(7−b)2+b2=25
49+b2−14b+b2=25
2b2−14b+24=0
b2−7b+12=0
(b−4)(b−3)=0
⇒b=4,3
a=7−b⇒a=3,4
Area=21×4×3=6sq. units
Answered by
3
Answer:
y=6,24....24 is not clearly written sorry for that
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