Question

A wire of length 82 cm is bent in the form of a rectangle such that its length is 9cm more than its breadth. The length of the rectangle so formed is

Answer 1

Step-by-step explanation:

given :breadth=x

length=x+9

perimeter of rectangle=82cm=2(l+b)

82=2(X+9+X)

82=2(2x+9)

82=4x+18

82-18/4=x

16=x

length=X+9

=16+9=25cm

Answer 2

$\huge\fcolorbox{black}{aqua}{Solution:-}$

✏️ Question:-

★ A wire of length 82 cm in bent in the form of a rectangle such that its length is 9 cm more than its breadth. Find the length and the breadth of the rectangle so formed.

✏️ Answer:-

★ Length of the rectangle = 25 cm.

✏️ Step-by-step explanation:-

★ Let the length of rectangle=l

⇒ breadth = l − 9

⇒ Perimeter of rectangle=2( l + b)= Length of wire

⇒2( l + l −9 ) = 82

⇒2l - 9 = 41

⇒2l = 41 + 9

⇒2l = 50

⇒l = 50/2

⇒l = 25 cm

Similarly,

⇒b = l - 9 = 25 - 9 = 16 cm.

∴ The respective length of the so called rectangle formed is 25 cm.

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I hope this helps! :)