Question

A wire of length 86 cm is bent in the form of a rectangle such that it's length is 7 cm more than its breadth. Find the length and the breadth of the rectangle so formed.

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{LENGTH=25cm}}}}}$

$\huge{\pink{\boxed{\green{\sf{BREADTH=18cm}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

☆ Let breadth be x

☆ length be x+7

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\orange{given}} \\ { \pink{ \boxed{ \green{perimeter \: of \: rectangle = 86cm}}}} \\ { \pink{ \boxed{ \green{length = x + 7}}}} \\ { \pink{ \boxed{ \green{breadth = x}}}} \\ \\ { \blue{ to \: find}} \\ { \purple{ \boxed{ \red{length = }}}} \\ { \purple{ \boxed{ \red{breadth= }}}}$

☆ According to given question:

$\to perimeter \: of \: rectangle = 86cm \\ \to 2(l + b) = 86 \\ \to 2(x + 7 + x) = 86 \\ \to 2x + 7 = \frac{86}{2} \\ \to 2x = 43 - 7 \\ \to 2x = 36 \\ \to x = \frac{36}{2} \\ { \boxed{ \to x = 18}} \\ \\ { \pink{ \boxed{ \green{ \therefore length = x + 7 = 18 + 7 = 25cm}}}} \\ { \pink{ \boxed{ \green{ \therefore breadth = x =18cm }}}}$

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