Question

a wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth find the length and the breadth of the rectangle so

Answer 1

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Let the length of rectangle=l

⇒ breadth=l−7

⇒ Perimeter of rectangle=2(l+b)= Length of wire

⇒2(l+l−7)=86

⇒2l−7=43

⇒2l=50

⇒l=25cm

⇒ Breadth=18cm.