Question

A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breath. find its l n b ​

Answer 1

Correct QuEsTiOn :-

A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breath. find its length and breadth formed .

Answer :-

Length = 25 cm

Breadth = 18 cm

Given :-

Total length of Wire= Perimeter Of Rectangle.

Length is 7 cm more than its breath.

Find :-

Length and breadth .

SoLuTioN :-

As we know ,

According to the Question :-

Its Length = 'x+7'

So, we consider , Its Breadth = 'x'

Perimeter Of Rectangle= Total length of Wire [Perimeter =

2 ( l +b)

putting the values :-

2(x + x +7) = 86

2x + 7 = 86/2

2x + 7 = 43

2x = 43 -7

2x = 36

So now ,

x = 18 cm = Breadth

Therefore ,

Length = x + 7

            = 18 + 7

            = 25 cm

✦ Length = 25 cm

✦ Breadth = 18 cm

Answer 2

☆ Question ☆

A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breath. find its l and b.

☆ Solution ☆

Given

• A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breath.

To find

• Its l and b .

Step-by-Step-Explaination

Total length of wire = Perimeter of rectangle

Let's its breadth = x

So its length = x + 7

Perimeter of rectangle = Total length of wire

As we know that

Perimeter of rectangle = 2 ( l + b )

2 ( x + x + 7 ) = 86

2x + 7 = $\frac{86}{2}$

2x + 7 = 43

2x = 43 - 7

2x = 36

x = 18

Therefore, Breadth = 18 cm

Length = 18 + 7

= 25 cm