Question

A wire of length 86 cm is bent in the form of a rectangle such

that its length is 7 cm more than its breadth .find the length and breadth of the rectangle so formed.

Answer 1

Answer:

As 86 is the perimeter so we have 7 as length then

A. T. Q

Perimeter = 2{ L + B }

( 2 × 7) ( 2 × B )

14 ×2B =86

2B = 86 - 14

B = 72 ÷ 2

B = 36

Hence proved .