Question

A wire of length 86cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth.Find the length and breadth of the rectangle so formed.

Answer 1

"A wire of length of 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth. Find the length and the breadth of. the rectangle so formed.

Answers

Given 
Length (L) = Breadth (B) + 7 
==> L = B +7 

perimeter of rectangle = 2(L +B) = 86 
==> 2L + 2B = 86 
==> 2(B+7) + 2B = 86 
==> 2B +14 + 2B = 86 
==> 4B = 72 
==> B = 18 

Length (L) = 18 + 7 
==> L = 25 
Rectangle will have 25cm Length and 18 cm Breadth

Answer 2

Let the breadth of rectangle be x.
Then, it's length =x+7
We know that
Perimeter of rectangle =2(l+b)

2{(x+7)+x} =86 cm
2x+7=86/2
2x =43-7
2x =36
X=36/2
X=18

So, the breadth of the rectangle is 18 cm.
And length =18+7
=25 cm.
I hope my answer help you.