A wire of length g and area of cross section A has a resistance of 10 ohms. What will be the resistance of the wire if the length is doubled?
Answers
resistance of wire is directly proportional to its length nd inversely proportional to its cross sectional area...
so by doubling the length .... resistance will also get doubled..
new resistance = 20 ohm
Correct Question
A wire of length 'l' and area of cross section 'A' has a resistance of 10 ohms. What will be the resistance of the wire if the length is doubled?
Solution-
Resistance of a wire is directly proportional to length of the wire and inversely proportional to the area of cross-section i.e. R ∝ l/A
If we remove the sign of proporinalty then there comes a constant i.e. p (rho = resistivity).
R = p l/A ................(1st equation)
As per given condition,
Length is doubled. If length is doubled then resistance also become doubled and area of cross-section becomes half.
Let's denote the new resistance by R'.
R' = p 2l/(A/2)
R' = p 4l/A
R' = 4 p l/A
Using 1st equation, we can say that
R' = 4R ...............(2nd equation)
And given in question that, resistance of wire is 10 ohm. Means R = 10 ohm.
So, substitute the value of R in (2nd equation)
R' = 4(10)
R' = 40 ohm
Therefore, the new resistance is 40 ohm.