Question

a wire of length l and area a is stretched in such a way that its length increase by 150 Percentage calculate new resistance​

Answer 1

Answer:

Correct option is

D

125%

Let initial length of the wire be l.

Resistance of the wire R=

V

ρl

2

New length of the wire l

′

=l+0.5l=1.5l

New resistance of the wire R

′

=

V

ρ(1.5l)

2

=2.25R

Percentage change in resistance

R

R

′

−R

×100=

R

2.25R−R

×100=125 %

Step-by-step explanation:

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