a wire of length L and area of cross section A was drawn into a wire of double its length by melting in if its original resistance where RAW and R respectively what will be its new resistance and resistivity
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Resistivity remains the same because it depends on the material which, here, is not changing.
The new resistance will become 4 times the original resistance.
We can find this by calculating because doubling the length leads to the area becoming half the original area.
As R= resistivity* l/a
Rnew/Rold= 4:1
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