A wire of length (l) and cross-section (A) was drawn into a wire of double of its length by melting it. If its
original resistance and resistivity were (p) and (R) respectively, what will be its new resistance and
resistivity?
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Answer:
r will be resistance of wire after melting =
R will before melting = 4R=r,,, resistivity will be 1/4
of its before resistivity
Explanation:
resistivity=let it be. X. (after melting)
we know 4R=r(here r is resistance of wire after melting....)
so. X= r×A/l
so. x=4r×A/l. x is resistivity after melting
X/x=. we get. X=4x
so it will help you
have a good day
thnx.
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