A wire of length l and resistance r is stretched so that its length is doubled.how will the resistance change
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R equals rho×length/A
So R is directly proportional to L
This applies that if L is doubled or if we substitute L as 2L ....
R=rho×(2L)/A
R=2 rho×L/A
So the resistance is also doubled
So R is directly proportional to L
This applies that if L is doubled or if we substitute L as 2L ....
R=rho×(2L)/A
R=2 rho×L/A
So the resistance is also doubled
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