Question

a wire of length l, area of cross section A and weight is subjected to external force 2w . if Y is young modolus ,then total extension in wire is​

Answer 1

Answer:

Total extension, I = [2w * l] / [A * Y] S.I. units.

Explanation:

Given data:  

Length of the wire, L = l

Area of cross section, A = A

External force, F = 2w

Young’s Modulus = Y

To find: total extension in the wire

Let us consider the extension in the wire be “I”.

The young’s modulus is defined as the ratio of the longitudinal stress and longitudinal strain within the elastic limits.

Y = [Longitudinal Stress] / [Longitudinal Strain] = [F/A] / [I/L] ….. (i)

Substituting the given values in equation (i) and solving for I, we get

I = [F * L] / [A * Y]

Or, I = [2w * l] / [A * Y] S.I. units

Hence, the total extension in the wire is given as, I = [2w * l] / [A * Y] S.I. units.

Hope this helps!!!!!