Question

A wire of length l is bent in the form of a circular loop with a number of turns and is suspended in a magnetic field of intensity



b. Find the the expression for the maximum torque produced on the circular loop when current i is passed tbrough it?

Answer 1

Answer:

Step-by-step explanation:

Visualise the question first.

We need to find the magnetic moment which is given as,

M=NIA

Where, N= Number of turns.

I= Current in the coil.

A= Area of the coil,which is a circle.

Now try to understand,

When the wire of length L is bent in the form of the circle, the perimeter of the circle will be L.

So, 2πr=L

⇒r=L2π

So you can find the area now which is,

A=πr2=π×L24π2=L24π

Here N=1

So magnetic moment has a magnitude of,

M=NIL24π

Direction :-

Suppose the coil is on the plane of the paper.

If the direction of current is clockwise then according to right hand thumb rule magnetic moment will be inward normal to the plane of paper(means ‘×’ magnetic moment)

If the direction of current is anticlockwise then the direction of magnetic moment is outward normal to the plane of paper(means ‘.’ magnetic moment)

I hope it helps