A wire of length L is placed in a magnetic field B, If the current in the wire is I, then maximum magnetic force on the wire is
Answers
Answer:
F = BIL
Explanation:
We know thatmagnetic force(F) acting on the wire of length (L) carrying current (I) placed in a magnetic field (B) is .
i.e. ...(1)
Now the force (F) is maximum when the value is maximum.
i.e. when then
Therefore equation (1) becomes F = BIL.
Hence, the maximum magnetic force acts on the wire is F = BIL.
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Answer:
The force on a section of wire of length L carrying a current I through a magnetic field B is
F = I (L × B)
F= ILB sin θ, where θ is angle between wire and magnetic field.
Explanation:
Using the principle of force on a moving charge, apply force to the conductor carrying the current:-
- Consider a metallic conductor with cross-sectional area A and length L that is positioned at an angle θ to the direction of a uniform magnetic field B.
- The conductor is carrying current I.
- According to the free-electron concept of metals, current in metals is caused by the mobility of free electrons.
- Everyfree-electron feels a force from a magnetic field when it is put in a conductor.
- The net force exerted on the conductor is the total of all forces acting on all electrons.
- If represents the drift speed of free electrons, then
Current I = ....(i)
In this equation, n denotes the number of free electrons per unit volume.
Magnetic force on each electron = θ ....(ii)
Its direction is perpendicular to both and
The volume of the conductor
∴ The total number of free electrons in the conductor =
Net magnetic force on each conductor
F= ( force on one electron) × ( number of electron)
θ ×
θ
Using equation (i)
θ
Force will be maximum when θ or θ =90°
That is when the length of the conductor is perpendicular to the magnetic field.
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