A wire of length L is stretched to four times it's length. Calculate the ratio of New resistance to original resistance.☝️✍
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R=pL/A
Since the length is 4time therefore it's cross section area will be 1/4 times
Now,
R' = (p×4L)/(A/4)
R' = 4×p×4L/A
R' = 16(pL/A)
R' = 16R
Ratio of R to R' = 1 : 16
Since the length is 4time therefore it's cross section area will be 1/4 times
Now,
R' = (p×4L)/(A/4)
R' = 4×p×4L/A
R' = 16(pL/A)
R' = 16R
Ratio of R to R' = 1 : 16
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