A wire of length l radius r is stretched by a force f and a second wire of same material with kength 2l and radius 2r is stretched with a force 2f then the ratio of elongation in the two wires is
Answers
Solution:
Let X be the second wire of the material of the wire,
X = F/πr^2 / l/L = FL / πr^2 l
------------(equation 1)
As both the wires are made up of same material, so their new wire is same.
Let the extension produced in second wire be l'.
Then,
X = 2F/π(2r)^2 / l'/2L = FL / πr^2 l' -------------(equation 2)
Equating (1) and (2), we get
FL / πr^2 l = FL / πr^2 l'
=> l' = l
So, the ratio of elongation in the two wires is 1:1.
Answer:1:1
Explanation:Let X be the second wire of the material of the wire,
X = F/πr^2 / l/L = FL / πr^2 l
------------(equation 1)
As both the wires are made up of same material, so their new wire is same.
Let the extension produced in second wire be l'.
Then,
X = 2F/π(2r)^2 / l'/2L = FL / πr^2 l' -------------(equation 2)
Equating (1) and (2), we get
FL / πr^2 l = FL / πr^2 l'
=> l' = l
So, the ratio of elongation in the two wires is 1:1.
