Question

A wire of length le 6+ 0.06cm and
radius r= o.5+- 0.005
and mass m=0.3 +-0.003 g
Maximum percentage error in density is ?
-​

Answer 1

Answer:

4%

Explanation:

Since density is mass÷volume,

For a cylinder it becomes- mass÷(pi×radius^2×length)

Relative percent errors for-

Mass-0.003÷0.3×100=1%

Radius^2-2×0.005÷0.5×100=2%

Length-0.06÷0.6×100=1%

THE UNITS CANCEL THEMSELVES FROM THE NUMERATOR AND DENOMINATOR.

therefore,

maximum percentage error in density-1%+2%+1%=4%

so, the answer is 4%