Math, asked by dhruvagarwal097, 1 month ago

. A wire of length of 36 cm is bent in the form of a semi-circle. What is the radius of the semi-circle?​

Answers

Answered by jyotiyadav427034
1

Step-by-step explanation:

So, the perimeter of a semicircle is πr+d, where r = radius and d = diameter of a semicircle. The length of a wire which bent in the form of a semicircle is equal to the perimeter of a semicircle. ∴ The radius of the semicircle is 7cm.

Answered by ritaarjun335
5

Answer:

7cm

Step-by-step explanation:

perimeter of wire and semicircle is same so

 \frac{2\pi  r}{2}  + d = 36  \\  \\ \pi r + 2r = 36 \\ r(\pi + 2) = 36 \\  \frac{22r + 14r}{7}  = 36 \\  \\  \frac{36r}{7}  = 36 \\  \\ 36r = 36 \times 7 \\ r = 7

the diameter is also counted for perimeter

because πr is for only outside one including inside diameter πr+d

refer attachment to get what I want to say

Attachments:

prince5132: Nice
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