A wire of mass 1 Kg and length 3m hanging from a ceiling is made to accelerate with acceleration of 6 m/s in the upward direction. Find the tension in the wire at 1 m from bottom of the wire?
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Answered by
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Answer:
2.1
Explanation:
m
Given,
f
1
=420H
z
f
2
=490H
z
Fundamental frequency =f
2
−f
1
=490−420=70Hz
We know, f=
2l
1
u
T
⇒l=
2l
1
6×10
−3
540
l=
2×70
1
6×10
−3
540
=
2×70
1
×
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2.1 I hope this will help you
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