A wire of mass m and length l is bent in the form of a circular ring. the moment of inertia of the ring about its axis is:
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I=MR²
where
I is the moment of inertia
M is the mass of the ring and
R is the radius of the ring
where
I is the moment of inertia
M is the mass of the ring and
R is the radius of the ring
Answered by
3
Answer:
(1/4π^2)ml^2
Explanation
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