Question

A wire of radius 1.5 mm and length
2.5 m is twisted through 90°. What
is the angle of shear at the surface?​

Answer 1

Answer:

Explanation:

A wire of radius 1.5 mm and length

2.5 m is twisted through 90°

r = 1.5mm = 1.5 × 10⁻³ m

Ф = 90°

l= 2.5

Ф = rФ / l

= 1.5 × 10⁻³ × 90 / 2.5

= 135 × 10⁻³ / 2.5

= 0.054°

angle of shear at the surface is 0.054°