A wire of radius 1mm and length 2m is twisted through90°. If the modulus of rigidity is 5.0 x 1010 N/m², Then (A) Angle of shear is 7.85 x 10-4 radians a point midway (B) Angle of shear is 7.85 x 10-4 radians on the surface. (C) Couple per unit twist is 3.92 x 10-2N – m/rad. (D) Torsional couple is 6.16 x 10-2N – m.
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Answer:
Correct option is B)
length = 5m = l
phi = 30 degrees
30 * pi/180 = pi/6 * r * a * d l*theta = r*phi
5(theta) = 10 ^ - 3 6
theta = 10 ^ - 3 * (pi/30) = 10 ^ - 1 * (3.14/3) * r * a * d
=(1.04667)*10^ -4 × (180)
=59.9697*10^ -4 *60 m
=0.3598 sec approx0.36
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Answer:
Angle of shear is 7.85 x 10-4 radians on the surface. (
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