a wire of radius r has resistance R if it is streached to the wire of radius r/2 then the resistence become
aarow:
diameter is the answer
2 times radius or 2r is also the diameter
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2R is the answer to this question
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Resistance = ρ L/A
{Given E :P}
is A {A=r} become A/2 = r/2
then
new R = ρ2L/(r/2)
=4(ρL/r)
so resistance become 4 times
Mark as Brailiest
how it becomes 2r it in 4r ....can u clear my doubt plz
Type + logical mistake
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