A wire of radius 'r' has resistance R. If it is stretched until its radius is 1/2 the original value,then find its resistance and resistivity.
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Answered by
8
Resistance = ρ L/A
is A become A/2
then
new R = ρL/(A/2)
=2(ρL/A)
so resistance become 2 times
is A become A/2
then
new R = ρL/(A/2)
=2(ρL/A)
so resistance become 2 times
Answered by
30
new resistance is 16 times the first one and resistivity is same because of same material
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