Question

a wire of resistance 1 ohm is drawn out so that its length is increased to twice its original length calculate its new resistance​

Answer 1

Explanation:

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Answer 2

Answer:

we have R=

A

ρL

if we increase the length the resistance is also increase

In this case length become 2L so R

1

=

A

ρ2L

=2R

R=5Ω

⇒R

1

=2×5=10Ω

new resistance is 10Ω ,resistivity is constant it is a matrial property

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