A wire of resistance 1 ohm is stretched twice its length. Then the percentage increase in its resistance is
a.100%
b.200%
c.300%
d.400%
Answers
Answered by
2
Answer:
200%
Explanation:
del R/R=del Rho/Rho +del L/L +DelA/A
delR/R=2
Multiply by 100 we get relative error as 200%
Hope you understand!
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Answered by
1
Answer:
200% is correct answer.
resistance is directly proportional to length.
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