a wire of resistance 10 ohm is bent in the form of a circle what is the resistance across a diameter of circle
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2.5 ohm
since two branches are parallel to each other so
1/R = 1 / R1 + 1/R2
and R1 = R2 = 5
as in diameter resistance will be half R / 2 = 10/ 2 = 5
so 1/R = 1 / 5 + 1/5
1/R = 2 / 5
R= 5/2
R = 2.5 ohm
since two branches are parallel to each other so
1/R = 1 / R1 + 1/R2
and R1 = R2 = 5
as in diameter resistance will be half R / 2 = 10/ 2 = 5
so 1/R = 1 / 5 + 1/5
1/R = 2 / 5
R= 5/2
R = 2.5 ohm
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