Question

A wire of resistance 10 ohm is elongatef by 10% . The resistance of elongatef wire is

Answer 1

The new resistance will be 12.1 ohm

Explanation:

Let original length of wire be L. As it has been elongated by 10 % of its length the new length becomes

L+L/10=11L/10

As Volume remains constant.  

L*A=11L/10*A’

A’ =10/11A

Substituting the values in equation  

Rnew= p*(l/A)

We get,

Rnew = 12.1 ohm