A wire of resistance 12Ω/m is bent to form a complete a circle of radius 10 cm. The resistance between its two diametrically opposite , A and B is ?
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Answer:
3 Ω
Explanation:
Resistance = 12Ω (Since its resistance and not resistivity, I changed a question little bit)
The lenth of the wire will be 2πr = 2×5Π = 10πcm
Resistivity of the wire will be ₱ = 12/10π Ω/cm
When wire is bent into a circle and the resistance between two diametrically opposite points is measured, wire seems to be in parallel arrangement. So,
1/Req = 1/R + 1/R
1/Req = 2/R
Req = R/2
Req = ₱(length)/2
Req = 12/10π × 5π/2
Req = 3 Ω
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