a wire of resistance 12 ohm is stretched to 40% of its original length its uniform area of cross section find the resistance of such stretched wire
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R'=n²R
=(.4)² X 12
=1.92 ohm
TarunguptaAce51:
how your formula right
it's a formula which derives in class 12th.
actually 1.92 is only the increment. the real answer is 12+1.92=13.92 ohm respectively.
R' = n²R = (1.4)²X12 = 23.52 ohm.
this is the right answer which you want
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