Question

A wire of resistance 12 ohms is cut into three identical parts each part is known stretched to double its length new resistance of each part will be

Answer 1

Answer:

16Ω

Explanation:

When a wire of resistance R is cut into n equal parts, then the resistance on each wire will be R/n, i.e., R'=R/n

When a wire of length L is stretched to n times, the resultant resistance will be n² times the original resistance, i.e.,R'=n²R

Here,

The resistance of the small wires= R/3 = 4Ω

When they are stretched to twice their size, R' = 2² 4

                                                                              = 16Ω

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