Question

A wire of resistance 16 ohm is bent in circle

Answer 1

Answer:

Step-by-step explanation:

Lets say the points A and B have 2 current paths :

One with resistance x Ohm

Another with resistance (16 - x) Ohm

These two are connected in parallel so effective resistance is : x(16-x)/16 = 0.25K

So,

x^2 - 16x + 4K = 0

Since x is real we have b^2 - 4 ac > 0 for teh above quadratic equation . Which gives :

16^2 - 4*4*k > 0

or , 16 > K > 0