A wire of resistance 18 ohm is bent to form an equilateral triangle . the resistance across any two vertices of the triangle is brainly
Answers
Answered by
105
Hi.
Hope this helps u!
Hope this helps u!
Attachments:
Rosedowson:
Pls mark d brainliest!
Answered by
60
Resistance is directly proportional to the length of the wire
when the wire is bent in the form of an equilateral triangle the length becomes one third of the total length since the equilateral triangle has three equal sides
hence the resistance also becomes one third of the initial resistance
Hence resistance across any edge
= 18/3
=6 ohms But across any two vertices Two resistors series are in series Hence total resistance is 6 + 6 =12 ohms It is in parallel with 6 ohm resistor Hence finally it will be 12 × 6 / 12 + 6 = 4 ohms Hope this helps.. If you like my answer then plse mark it the brainliest .
when the wire is bent in the form of an equilateral triangle the length becomes one third of the total length since the equilateral triangle has three equal sides
hence the resistance also becomes one third of the initial resistance
Hence resistance across any edge
= 18/3
=6 ohms But across any two vertices Two resistors series are in series Hence total resistance is 6 + 6 =12 ohms It is in parallel with 6 ohm resistor Hence finally it will be 12 × 6 / 12 + 6 = 4 ohms Hope this helps.. If you like my answer then plse mark it the brainliest .
Similar questions