A wire of resistance 18 ohms is bent to formally triangle resistance across any two vertices
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We know resistance is directly proportional to length. So resistance across each side will be 18/3= 6
Now, between two vertices, 2 resistances are in series with each other (so 6+6 = 12 ) which are together parallel to the third resistance ( so 12×6/12+6= 12×6/18= 4)
The answer must be 4 ohm. Is it right?
Now, between two vertices, 2 resistances are in series with each other (so 6+6 = 12 ) which are together parallel to the third resistance ( so 12×6/12+6= 12×6/18= 4)
The answer must be 4 ohm. Is it right?
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