A wire of resistance 18 ohms is drawn until it's radius 1/2th of its original radius then resistance of the wire is
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Answer:
288Ω
Explanation:
volume remains constant
radius halved
area becomes 1/4th
length becomes 4 times(volume conservation)
R proportional to L/A
R increases 16 times
Resistance = 18×16 = 288Ω
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