Math, asked by niya1694, 1 year ago

A wire of resistance 2 ohm is stretched to double it's length such that its volume remains constant. What is the resistance of the stretched ? What will be the change in its resistivity? Explain the answer this is for 3 marks

Answers

Answered by navadeep7

The resistance of a uniform wire is directly proportional to its length and inversely proportional to its cross-sectional area. Here, R is theresistance of the wire in ohms, l is thelength of the wire in meters, and A is the cross-sectional area of the wire in .

Hope it helps you
Please make me as brainliest

niya1694: Thankyou..but these 2 adm

niya1694: But these 2 are not the answers.I asked the resistance with 2 ohm

navadeep7: please make me as brainliest

navadeep7: Thanks

niya1694: It's ok..

Answered by tanvirmondal200

we know
R=p. l/A........(1)
the volume of the conductor is (v)= A/2 into 2L(as volume is constant)
R'=p. 2L/A/2
=p. 4L/A
=4 L/A
=4R
if the resistance is two ohm then the value of R is 2
R'=4R
#R'=4 into 2
#R'=8
°•°R'=8 ohm

niya1694: But this is not the a

niya1694: This is not the answer

tanvirmondal200: mean??

tanvirmondal200: you want to mean my answer was wrong

tanvirmondal200: X+y/3a-b = y+z/3b-c = z+x/3c-a
Then show that x+y+z/a+b+c
= ax+by+cz/a^2+b^2+c^2

tanvirmondal200: please solve this

niya1694: For what reason you are asking me to solve this ?If you don't know the answer add it as a question...

niya1694: Sry it was my mistake the answer is 8 ohm only I was telling about the first answer

navadeep7: please make me as brainliest

niya1694: I have done

Previous Question

Next Question